Ok, you asked for this !!!
I have made a few assumptions, simplifications and rounding in the following - all calculations are at standard Temperature (273K), density of water is taken as 1kg/l (sea water is denser), and it is assumed that you know what a mole is (though that is not essential).
1 mole of air at STP has a volume of 22.4 litres, (imagine 22 cartons of orange juice) and a mass of 0.029 kg.
In order to increase the density of air, we must compress it into a smaller volume (ie apply a pressure). For it to sink, it must have a density greater than water.
To have the same density as water (for ease of calculation), we must compress our 0.029 kg of air into 0.029 litres (that's about 2 tablespoons)
So that; density = mass / volume = 0.029 / 0.029 = 1kg / litre
The pressure, P, required to compress our mole of air into this small volume is given by the Ideal Gas Law,
PV = nRT
where P = Pressure, V = Volume, n = no. of moles T = Temperature (in Kelvin) and R is the gas constant = 8.3145 (for pressures in kPa)
So;
PV = nRT => P = nRT/V
=> P = {1 x 8.3145 x 273} / 0.029
=> P = 78271 kPa (kiloPascals, a unit of pressure)
[Cont�.]