Solubility

[ChemStump]

I had to take a sample of salt water and weight it. Subtracted from the weight of the dish the salt water solution was 5.5 grams. Afterwards I evaporated. The solute left in the dish (salt i guess) subracted from the dish was 4 grams. Determine the solubility based on these results, and these results alone please :)

[brachiopod]

Solubility is normally measured in grammes of solute per volume (usually cm cubed) of solvent.

Or; g per cm^3

Or; g divided by cm^3

In your question, you are given...err... sorry ,you measured the mass of the solution.

Now pure water has a density of 1g per cm^3.

So if you had 5.5g of solution, and after evaporation, are left with 4g of salt, then you can;

i) work out the mass of water and therefore, (given the density of water above) the volume of water.

ii) work out he solubility, since you know the mass of salt and you know noe the volume of water.

[ remember, Solubility = g / cm^3 or mass divided by volume ]

Reply back if you are still stuck.

[brachiopod]

OK, ignore my last answer - I've just seen the previous time you posted this question....

Check your results.

Your figures suggest that you were deep within the realms of super-saturated solutions