The original question said that the units are 10W halogen, and that the secondary of the transformers are 12v and 834mA. As Watts = Volts x Amps then 12 x 0.834 = 10.008 and there is your 10 Watts. However, the cable to the primary is at the higher pressure of 240 Volts. Now, the same current (834mA) will flow in this circuit with the addition of some transformer inefficiencies (heat and magnetic leakage) say 20% to be really gloomy. So the current required at the primary will be 834mA + 167mA = 1A. Now, as there will be three of these units drawing current then the maximum loading on the mains will be 3 Amps which calculates back to 3 x 240 = 720 Watts.
The 3 Amp cable should be fine, provided that the insulation is rated for high voltages and is double (each wire is enclosed in PVC and the whole is within a second PVC sheath, and that the cable is not squeezed by clips, passing through holes, or tight bends. Keep the radius of the bends to more than eight times the diameter of the cable.