Lottery

[TheEpsilon]

How many different combinations of 6 numbers are in the numbers 1 to 49

[TOMMO33]

The first can be any of 49, the second any of the 48 remaining, the third any of the other 47, and so on, so you need to multiply 49 x 48 x 47 x 46 x 45 x 44. I'll leave you to work it out, but you'll gather that chances of all six right are pretty slim.

[Harry-Wragg]

13,983,816

[TheEpsilon]

Thanx guys , my daughters plan to cover every permutation is a non starter then . ta

[TOMMO33]

HarryWragg's answer is correct. I forgot to mention that, after multiplying the six numbers together, you would have to divide the answer by 6 x 5 x 4 x 3 x 2 x 1. That's to eliminate duplications.
So a mere 14 million to 1. I guess she'll just have to await for a super super jackpot, and hope that she doesn't have to share it with anybody.