Donate SIGN UP

Scott & Bailey...

Avatar Image
Jemisa | 23:59 Mon 19th Mar 2012 | Film, Media & TV
11 Answers
I'm enjoying the new series of 'Scott & Bailey and have just realised that the actress playing Nadia is the one that played a Dingle in 'Emerdale' a few years back.
For the life of me I cant remember her name. OOooo! its just come to me
Lisa Riley.... Am I right?
She seems to have piled the pounds on too, never-the-less she's still a good actress.

jem
Gravatar

Answers

1 to 11 of 11rss feed

Best Answer

No best answer has yet been selected by Jemisa. Once a best answer has been selected, it will be shown here.

For more on marking an answer as the "Best Answer", please visit our FAQ.
Yes Jem, you are right. She was a big lass in Emmerdale though....don't know if she's put any extra on.
Question Author
I think Mrs C she's a bit of a yo-yo. I remember her on Richard & Judy a few years back & she'd slimmed down quite a lot they even remarked on it.
(maybe she was wearing padding)

jem
I am enjoying it too, just been watching on iplayer.
I've not seen her on the telly for ages. Mind you, I don't watch much telly. I do remember her presenting You've Been Framed.
Ahhhh - got her now. Is that really her ?
Aye, Anna.
I enjoyed it tonight but, wish they wouldn't have us to wait for the next episode from last week as I forgot most of it.
That is where ITV player comes in handy.
Me too trt, I was struggling to remember what had happened from the week before. Iplayer is not so good for me as I like to have subtitles on.
I discovered this programme last week and I love it! And yes Lisa Riley does look a lot bigger to me.
Question Author
Yes, I remember her too doing 'You've Been Framed' shes a good actress and although big makes a good character after all there are a lot of big people in this world & TV progs should portray them more especially soaps although EE has got Helen. Don't remember anyone in Corrie.
Perhaps the prod's think its not PC.

jem

1 to 11 of 11rss feed

Do you know the answer?

Scott & Bailey...

Answer Question >>