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Two Trains on a railway track
26 Answers
Two trains are travelling on the same railway track, which is 1 dimensional and long. Train one is at a position x=-5km and train 2 is at x=10km. Train two is travelling at a velocity of 90m/s, whilst train one is travelling -100m/s. If, at these positions and velocities, the trains were to brake and experience a deceleration of magnitude 20m/s/s, would they crash?
You may assume that there is nothing else causing deceleration
You may assume that there is nothing else causing deceleration
Answers
If train one has negative velocity it must be going backwards (or in the opposite direction) so they won't ever meet anyway.
19:21 Tue 29th May 2012
The way you have worded the question, with train one going backwards at 100 m/s and train two going forwards at 90 m/s the trains would never meet. No need for a calculation, they are going in opposite directions.
The trains stop well within the kilometres of separation between them so I would suspect a trick question.
Newton's first equation of motion: v = u + at
Second equation: s = ut + 1/2 at^2
Third: v^2 = u^2 + 2as
Using third equation to calculate distance to stop:
Train travelling at -100 m/s 0 = 10000 + 40 x s so s is - 250m
Train travelling at 90 m/s 0 = 8100 - 40 x s so s is 225 m
(Acceleration and deceleration are directional (vector quantities) so deceleration can have a negative sign as above).
If I were answering the question I would draw a quick graph showing the directions of travel and put in the quick calculation above to show that you have understood the maths and physics even if I had made a mistake taking down the question.
The trains stop well within the kilometres of separation between them so I would suspect a trick question.
Newton's first equation of motion: v = u + at
Second equation: s = ut + 1/2 at^2
Third: v^2 = u^2 + 2as
Using third equation to calculate distance to stop:
Train travelling at -100 m/s 0 = 10000 + 40 x s so s is - 250m
Train travelling at 90 m/s 0 = 8100 - 40 x s so s is 225 m
(Acceleration and deceleration are directional (vector quantities) so deceleration can have a negative sign as above).
If I were answering the question I would draw a quick graph showing the directions of travel and put in the quick calculation above to show that you have understood the maths and physics even if I had made a mistake taking down the question.
It's a while since I've done this ort of maths but I'm not sure the use of a minus sign makes it a trick question. Isn't velocity also a vector so that can be positive or negative depending on the direction of travel. Train 1 could be travelling East at 90m/s; train 2 could be heading West (towards it) at 100m/s and shown as minus